The Magnitude of a Particle’s Vector

Part 1

A particle has a trajectory given as \(\vec{r} = (\) \(3t^2 - 8t\) \() \hat{\imath} + (\) \(2t^2 + 6t\) \() \hat{\jmath}\) \(m\) for \(t\) given in seconds. What is the magnitude of the acceleration vector for this particle at \(t = \) \(14\) \(s\)?

Answer Section

Please enter in a numeric value in \( {m/s}^2\).

Attribution

Problem is licensed under the CC-BY-NC-SA 4.0 license.